Base | Representation |
---|---|
bin | 1100011001111001101… |
… | …0011110111100010000 |
3 | 202101002002012121112100 |
4 | 3012132122132330100 |
5 | 11442422422440422 |
6 | 241522451200400 |
7 | 21253043542203 |
oct | 3063632367420 |
9 | 671062177470 |
10 | 213111140112 |
11 | 8241a756892 |
12 | 353765a6100 |
13 | 17133735150 |
14 | a4594db93a |
15 | 582452b7ac |
hex | 319e69ef10 |
213111140112 has 120 divisors (see below), whose sum is σ = 670219228224. Its totient is φ = 62721660672.
The previous prime is 213111140107. The next prime is 213111140113. The reversal of 213111140112 is 211041111312.
It is a Harshad number since it is a multiple of its sum of digits (18).
It is not an unprimeable number, because it can be changed into a prime (213111140113) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 2431758 + ... + 2517869.
Almost surely, 2213111140112 is an apocalyptic number.
It is an amenable number.
213111140112 is an abundant number, since it is smaller than the sum of its proper divisors (457108088112).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
213111140112 is a wasteful number, since it uses less digits than its factorization.
213111140112 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4949677 (or 4949668 counting only the distinct ones).
The product of its (nonzero) digits is 48, while the sum is 18.
Adding to 213111140112 its reverse (211041111312), we get a palindrome (424152251424).
The spelling of 213111140112 in words is "two hundred thirteen billion, one hundred eleven million, one hundred forty thousand, one hundred twelve".
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