Base | Representation |
---|---|
bin | 1001101111001001101101… |
… | …10110111110000001011000 |
3 | 2210210220101120021022220202 |
4 | 10313210312312332001120 |
5 | 10301300402040200130 |
6 | 113312121424241332 |
7 | 4336626530041223 |
oct | 467446666760130 |
9 | 83726346238822 |
10 | 21411332350040 |
11 | 6905549a12676 |
12 | 24997aba70248 |
13 | bc410692b879 |
14 | 54045792c5ba |
15 | 271e57d34145 |
hex | 137936dbe058 |
21411332350040 has 32 divisors (see below), whose sum is σ = 50270084650080. Its totient is φ = 8192161942272.
The previous prime is 21411332350039. The next prime is 21411332350061. The reversal of 21411332350040 is 4005323311412.
It is a junction number, because it is equal to n+sod(n) for n = 21411332349985 and 21411332350012.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 11636592749 + ... + 11636594588.
It is an arithmetic number, because the mean of its divisors is an integer number (1570940145315).
Almost surely, 221411332350040 is an apocalyptic number.
21411332350040 is a gapful number since it is divisible by the number (20) formed by its first and last digit.
It is an amenable number.
21411332350040 is an abundant number, since it is smaller than the sum of its proper divisors (28858752300040).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
21411332350040 is a wasteful number, since it uses less digits than its factorization.
21411332350040 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 23273187371 (or 23273187367 counting only the distinct ones).
The product of its (nonzero) digits is 8640, while the sum is 29.
Adding to 21411332350040 its reverse (4005323311412), we get a palindrome (25416655661452).
The spelling of 21411332350040 in words is "twenty-one trillion, four hundred eleven billion, three hundred thirty-two million, three hundred fifty thousand, forty".
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