Base | Representation |
---|---|
bin | 1110010001110111000110… |
… | …00010111100101000000000 |
3 | 11010011210221101120111011111 |
4 | 13020323203002330220000 |
5 | 13103424220123300100 |
6 | 150440545313253104 |
7 | 6420401525235151 |
oct | 710734302745000 |
9 | 133153841514144 |
10 | 31400020134400 |
11 | a006745850645 |
12 | 363164b264194 |
13 | 146a017275768 |
14 | 7a7aaa517928 |
15 | 396bbeab46ba |
hex | 1c8ee30bca00 |
31400020134400 has 60 divisors (see below), whose sum is σ = 77796003041262. Its totient is φ = 12560008048640.
The previous prime is 31400020134323. The next prime is 31400020134433. The reversal of 31400020134400 is 443102000413.
It can be written as a sum of positive squares in 3 ways, for example, as 14429179627776 + 16970840506624 = 3798576^2 + 4119568^2 .
It is a super-2 number, since 2×314000201344002 (a number of 28 digits) contains 22 as substring.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 1226550487 + ... + 1226576086.
Almost surely, 231400020134400 is an apocalyptic number.
It is an amenable number.
31400020134400 is an abundant number, since it is smaller than the sum of its proper divisors (46395982906862).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
31400020134400 is an equidigital number, since it uses as much as digits as its factorization.
31400020134400 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2453126601 (or 2453126580 counting only the distinct ones).
The product of its (nonzero) digits is 1152, while the sum is 22.
Adding to 31400020134400 its reverse (443102000413), we get a palindrome (31843122134813).
The spelling of 31400020134400 in words is "thirty-one trillion, four hundred billion, twenty million, one hundred thirty-four thousand, four hundred".
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