Base | Representation |
---|---|
bin | 1001101010011101001… |
… | …10100001000000010100 |
3 | 1011202000211021122111000 |
4 | 10311032212201000110 |
5 | 20414444441420200 |
6 | 412311044543300 |
7 | 32663020434021 |
oct | 4651646410024 |
9 | 1152024248430 |
10 | 332031201300 |
11 | 1188a4a58997 |
12 | 544246b1b30 |
13 | 25405c73a66 |
14 | 120db248548 |
15 | 89847b0300 |
hex | 4d4e9a1014 |
332031201300 has 144 divisors (see below), whose sum is σ = 1067880401280. Its totient is φ = 88503367680.
The previous prime is 332031201289. The next prime is 332031201319. The reversal of 332031201300 is 3102130233.
332031201300 is a `hidden beast` number, since 3 + 320 + 312 + 0 + 1 + 30 + 0 = 666.
It is a super-2 number, since 2×3320312013002 (a number of 24 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (18).
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 6516724 + ... + 6567476.
It is an arithmetic number, because the mean of its divisors is an integer number (7415836120).
Almost surely, 2332031201300 is an apocalyptic number.
332031201300 is a gapful number since it is divisible by the number (30) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 332031201300, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (533940200640).
332031201300 is an abundant number, since it is smaller than the sum of its proper divisors (735849199980).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
332031201300 is a wasteful number, since it uses less digits than its factorization.
332031201300 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 53199 (or 53186 counting only the distinct ones).
The product of its (nonzero) digits is 324, while the sum is 18.
Adding to 332031201300 its reverse (3102130233), we get a palindrome (335133331533).
The spelling of 332031201300 in words is "three hundred thirty-two billion, thirty-one million, two hundred one thousand, three hundred".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.074 sec. • engine limits •