Base | Representation |
---|---|
bin | 110000011110010000111… |
… | …000001110010100001000 |
3 | 102210102222020012111012110 |
4 | 300132100320032110020 |
5 | 414033422224442300 |
6 | 11030130523542320 |
7 | 462442015325103 |
oct | 60362070162410 |
9 | 12712866174173 |
10 | 3331030312200 |
11 | 1074755853898 |
12 | 4596ab38a9a0 |
13 | 1b2165314b96 |
14 | b731924173a |
15 | 5b9ab1e9550 |
hex | 30790e0e508 |
3331030312200 has 96 divisors (see below), whose sum is σ = 10341817277760. Its totient is φ = 886930809600.
The previous prime is 3331030312187. The next prime is 3331030312237. The reversal of 3331030312200 is 22130301333.
It is a super-2 number, since 2×33310303122002 (a number of 26 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 3802884 + ... + 4596083.
It is an arithmetic number, because the mean of its divisors is an integer number (107727263310).
Almost surely, 23331030312200 is an apocalyptic number.
3331030312200 is a gapful number since it is divisible by the number (30) formed by its first and last digit.
It is an amenable number.
3331030312200 is an abundant number, since it is smaller than the sum of its proper divisors (7010786965560).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
3331030312200 is a wasteful number, since it uses less digits than its factorization.
3331030312200 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 8399647 (or 8399638 counting only the distinct ones).
The product of its (nonzero) digits is 972, while the sum is 21.
Adding to 3331030312200 its reverse (22130301333), we get a palindrome (3353160613533).
The spelling of 3331030312200 in words is "three trillion, three hundred thirty-one billion, thirty million, three hundred twelve thousand, two hundred".
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