3340101300 has 72 divisors (see below), whose sum is σ = 9754438176. Its totient is φ = 882360960.

The previous prime is 3340101283. The next prime is 3340101319. The reversal of 3340101300 is 31010433.

It is a super-2 number, since 2×3340101300² = 22312553388523380000, which contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (15).

It is a self number, because there is not a number n which added to its sum of digits gives 3340101300.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 19927 + ... + 84126.

It is an arithmetic number, because the mean of its divisors is an integer number (135478308).

Almost surely, 2^3340101300 is an apocalyptic number.

3340101300 is a gapful number since it is divisible by the number (30) formed by its first and last digit.

It is an amenable number.

3340101300 is an abundant number, since it is smaller than the sum of its proper divisors (6414336876).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

3340101300 is a wasteful number, since it uses less digits than its factorization.

3340101300 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 104177 (or 104170 counting only the distinct ones).

The product of its (nonzero) digits is 108, while the sum is 15.

The square root of 3340101300 is about 57793.6095083185. The cubic root of 3340101300 is about 1494.8118986466.

Adding to 3340101300 its reverse (31010433), we get a palindrome (3371111733).

The spelling of 3340101300 in words is "three billion, three hundred forty million, one hundred one thousand, three hundred".