Base | Representation |
---|---|
bin | 111111000001110000011… |
… | …110101111011001110000 |
3 | 120100001121202112101110001 |
4 | 333001300132233121300 |
5 | 1031430311310003130 |
6 | 13113422102315344 |
7 | 624630344520223 |
oct | 77016036573160 |
9 | 16301552471401 |
10 | 4331214141040 |
11 | 141a948517046 |
12 | 59b502a28b54 |
13 | 25557c6c5287 |
14 | 10d8bbc5b5ba |
15 | 779e8b736ca |
hex | 3f0707af670 |
4331214141040 has 80 divisors (see below), whose sum is σ = 10432708022880. Its totient is φ = 1670273346560.
The previous prime is 4331214141031. The next prime is 4331214141073. The reversal of 4331214141040 is 401414121334.
It is a tau number, because it is divible by the number of its divisors (80).
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 191835 + ... + 2949445.
It is an arithmetic number, because the mean of its divisors is an integer number (130408850286).
Almost surely, 24331214141040 is an apocalyptic number.
4331214141040 is a gapful number since it is divisible by the number (40) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 4331214141040, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (5216354011440).
4331214141040 is an abundant number, since it is smaller than the sum of its proper divisors (6101493881840).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
4331214141040 is a wasteful number, since it uses less digits than its factorization.
4331214141040 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2758330 (or 2758324 counting only the distinct ones).
The product of its (nonzero) digits is 4608, while the sum is 28.
Adding to 4331214141040 its reverse (401414121334), we get a palindrome (4732628262374).
The spelling of 4331214141040 in words is "four trillion, three hundred thirty-one billion, two hundred fourteen million, one hundred forty-one thousand, forty".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.075 sec. • engine limits •