Base | Representation |
---|---|
bin | 101111100110000010… |
… | …110011001111101101 |
3 | 11212220112102222220100 |
4 | 233212002303033231 |
5 | 1314130124243000 |
6 | 35251002541313 |
7 | 3456256654452 |
oct | 574602631755 |
9 | 155815388810 |
10 | 51104134125 |
11 | 1a744a513a0 |
12 | 9aa2807839 |
13 | 4a8573a325 |
14 | 268b227829 |
15 | 14e1795a00 |
hex | be60b33ed |
51104134125 has 96 divisors (see below), whose sum is σ = 104868691200. Its totient is φ = 23700336000.
The previous prime is 51104134121. The next prime is 51104134181. The reversal of 51104134125 is 52143140115.
51104134125 is a `hidden beast` number, since 511 + 0 + 4 + 134 + 12 + 5 = 666.
It is not a de Polignac number, because 51104134125 - 22 = 51104134121 is a prime.
It is a super-2 number, since 2×511041341252 (a number of 22 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (51104134121) by changing a digit.
It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 194851 + ... + 374399.
It is an arithmetic number, because the mean of its divisors is an integer number (1092382200).
Almost surely, 251104134125 is an apocalyptic number.
51104134125 is a gapful number since it is divisible by the number (55) formed by its first and last digit.
It is an amenable number.
51104134125 is an abundant number, since it is smaller than the sum of its proper divisors (53764557075).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
51104134125 is a wasteful number, since it uses less digits than its factorization.
51104134125 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 179604 (or 179591 counting only the distinct ones).
The product of its (nonzero) digits is 2400, while the sum is 27.
The spelling of 51104134125 in words is "fifty-one billion, one hundred four million, one hundred thirty-four thousand, one hundred twenty-five".
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