Base | Representation |
---|---|
bin | 111100010001111001011100… |
… | …0110111010100001111011000 |
3 | 2120112101001110001220211100020 |
4 | 1320203302320313110033120 |
5 | 1023444203111424244420 |
6 | 5115410104333510440 |
7 | 216453343542153564 |
oct | 17043627067241730 |
9 | 2515331401824306 |
10 | 530225404134360 |
11 | 143a45370760190 |
12 | 4b57529b042420 |
13 | 199b206c2b696c |
14 | 94d10917d06a4 |
15 | 41475a604c340 |
hex | 1e23cb8dd43d8 |
530225404134360 has 128 divisors (see below), whose sum is σ = 1735288797346560. Its totient is φ = 128539072908800.
The previous prime is 530225404134331. The next prime is 530225404134379. The reversal of 530225404134360 is 63431404522035.
It is a super-2 number, since 2×5302254041343602 (a number of 30 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 647144314 + ... + 647963126.
It is an arithmetic number, because the mean of its divisors is an integer number (13556943729270).
Almost surely, 2530225404134360 is an apocalyptic number.
It is an amenable number.
530225404134360 is an abundant number, since it is smaller than the sum of its proper divisors (1205063393212200).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
530225404134360 is a wasteful number, since it uses less digits than its factorization.
530225404134360 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1309409 (or 1309405 counting only the distinct ones).
The product of its (nonzero) digits is 1036800, while the sum is 42.
Adding to 530225404134360 its reverse (63431404522035), we get a palindrome (593656808656395).
The spelling of 530225404134360 in words is "five hundred thirty trillion, two hundred twenty-five billion, four hundred four million, one hundred thirty-four thousand, three hundred sixty".
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