Base | Representation |
---|---|
bin | 11000010000100001001000… |
… | …10000111011010110011100 |
3 | 20222212122110012111011021122 |
4 | 30020100210100323112130 |
5 | 23442442210132433000 |
6 | 305241535305550112 |
7 | 14143661403412031 |
oct | 1410204420732634 |
9 | 228778405434248 |
10 | 53344102233500 |
11 | 15aa711a03a921 |
12 | 5b9653baa5338 |
13 | 239c433c9ba20 |
14 | d25c22977388 |
15 | 627908766085 |
hex | 30842443b59c |
53344102233500 has 48 divisors (see below), whose sum is σ = 125465328468480. Its totient is φ = 19696283899200.
The previous prime is 53344102233497. The next prime is 53344102233547. The reversal of 53344102233500 is 533220144335.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 4103385980 + ... + 4103398979.
It is an arithmetic number, because the mean of its divisors is an integer number (2613861009760).
Almost surely, 253344102233500 is an apocalyptic number.
53344102233500 is a gapful number since it is divisible by the number (50) formed by its first and last digit.
It is an amenable number.
53344102233500 is an abundant number, since it is smaller than the sum of its proper divisors (72121226234980).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
53344102233500 is a wasteful number, since it uses less digits than its factorization.
53344102233500 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 8206784991 (or 8206784979 counting only the distinct ones).
The product of its (nonzero) digits is 129600, while the sum is 35.
Adding to 53344102233500 its reverse (533220144335), we get a palindrome (53877322377835).
The spelling of 53344102233500 in words is "fifty-three trillion, three hundred forty-four billion, one hundred two million, two hundred thirty-three thousand, five hundred".
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