Base | Representation |
---|---|
bin | 100110110100011111111… |
… | …0110000111001011110000 |
3 | 200220001122122000120210010 |
4 | 1031220333312013023300 |
5 | 1144403420124001230 |
6 | 15203020334334520 |
7 | 1060320460144146 |
oct | 115507766071360 |
9 | 20801578016703 |
10 | 5335420531440 |
11 | 177781488333a |
12 | 72205965a440 |
13 | 2c91882963cc |
14 | 146342bc1596 |
15 | 93bbe82c9b0 |
hex | 4da3fd872f0 |
5335420531440 has 80 divisors (see below), whose sum is σ = 16600836335616. Its totient is φ = 1417528684800.
The previous prime is 5335420531439. The next prime is 5335420531447. The reversal of 5335420531440 is 441350245335.
It is a tau number, because it is divible by the number of its divisors (80).
It is a super-3 number, since 3×53354205314403 (a number of 39 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (5335420531447) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 40951416 + ... + 41081495.
Almost surely, 25335420531440 is an apocalyptic number.
It is an amenable number.
5335420531440 is an abundant number, since it is smaller than the sum of its proper divisors (11265415804176).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
5335420531440 is a wasteful number, since it uses less digits than its factorization.
5335420531440 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 82033198 (or 82033192 counting only the distinct ones).
The product of its (nonzero) digits is 432000, while the sum is 39.
Adding to 5335420531440 its reverse (441350245335), we get a palindrome (5776770776775).
The spelling of 5335420531440 in words is "five trillion, three hundred thirty-five billion, four hundred twenty million, five hundred thirty-one thousand, four hundred forty".
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