Base | Representation |
---|---|
bin | 100111010011000000111… |
… | …1110000110111100010111 |
3 | 201010022210210121201202121 |
4 | 1032212001332012330113 |
5 | 1201442123313331203 |
6 | 15253055245320411 |
7 | 1065130454132422 |
oct | 116460176067427 |
9 | 21108723551677 |
10 | 5400954433303 |
11 | 17a2593a7a810 |
12 | 7328a8866107 |
13 | 302400377230 |
14 | 14959c5d49b9 |
15 | 95757cea0bd |
hex | 4e981f86f17 |
5400954433303 has 64 divisors (see below), whose sum is σ = 6734820193920. Its totient is φ = 4255270502400.
The previous prime is 5400954433213. The next prime is 5400954433307. The reversal of 5400954433303 is 3033344590045.
It is a cyclic number.
It is not a de Polignac number, because 5400954433303 - 29 = 5400954432791 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 5400954433303.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (5400954433307) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 2522630613 + ... + 2522632753.
It is an arithmetic number, because the mean of its divisors is an integer number (105231565530).
Almost surely, 25400954433303 is an apocalyptic number.
5400954433303 is a deficient number, since it is larger than the sum of its proper divisors (1333865760617).
5400954433303 is a wasteful number, since it uses less digits than its factorization.
5400954433303 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4228.
The product of its (nonzero) digits is 1166400, while the sum is 43.
The spelling of 5400954433303 in words is "five trillion, four hundred billion, nine hundred fifty-four million, four hundred thirty-three thousand, three hundred three".
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