Base | Representation |
---|---|
bin | 111000110100110110… |
… | …000000000101011100 |
3 | 12211111022120201102120 |
4 | 320310312000011130 |
5 | 1444430111113000 |
6 | 44010323022540 |
7 | 4260015256506 |
oct | 706466000534 |
9 | 184438521376 |
10 | 61016113500 |
11 | 23971007191 |
12 | b9aa20aa50 |
13 | 59a5119794 |
14 | 2d4b7d6d76 |
15 | 18c1a686a0 |
hex | e34d8015c |
61016113500 has 96 divisors (see below), whose sum is σ = 185404197888. Its totient is φ = 15563521600.
The previous prime is 61016113489. The next prime is 61016113511. The reversal of 61016113500 is 531161016.
It is an interprime number because it is at equal distance from previous prime (61016113489) and next prime (61016113511).
It is a super-2 number, since 2×610161135002 (a number of 22 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 849792 + ... + 918791.
It is an arithmetic number, because the mean of its divisors is an integer number (1931293728).
Almost surely, 261016113500 is an apocalyptic number.
61016113500 is a gapful number since it is divisible by the number (60) formed by its first and last digit.
It is an amenable number.
61016113500 is an abundant number, since it is smaller than the sum of its proper divisors (124388084388).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
61016113500 is a wasteful number, since it uses less digits than its factorization.
61016113500 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1768628 (or 1768616 counting only the distinct ones).
The product of its (nonzero) digits is 540, while the sum is 24.
Adding to 61016113500 its reverse (531161016), we get a palindrome (61547274516).
The spelling of 61016113500 in words is "sixty-one billion, sixteen million, one hundred thirteen thousand, five hundred".
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