100132112301120 has 84 divisors (see below), whose sum is σ = 344412744612300. Its totient is φ = 26701896612864.

The previous prime is 100132112301047. The next prime is 100132112301163. The reversal of 100132112301120 is 21103211231001.

100132112301120 is a `hidden beast` number, since 1 + 0 + 0 + 1 + 321 + 1 + 230 + 112 + 0 = 666.

It can be written as a sum of positive squares in 2 ways, for example, as 52381579950144 + 47750532350976 = 7237512^2 + 6910176^2 .

It is a Harshad number since it is a multiple of its sum of digits (18).

It is a junction number, because it is equal to n+sod(n) for n = 100132112301093 and 100132112301102.

It is an unprimeable number.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 17384044395 + ... + 17384050154.

It is an arithmetic number, because the mean of its divisors is an integer number (4100151721575).

Almost surely, 2^{100132112301120} is an apocalyptic number.

100132112301120 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

100132112301120 is an abundant number, since it is smaller than the sum of its proper divisors (244280632311180).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

100132112301120 is a wasteful number, since it uses less digits than its factorization.

100132112301120 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 34768094572 (or 34768094559 counting only the distinct ones).

The product of its (nonzero) digits is 72, while the sum is 18.

Adding to 100132112301120 its reverse (21103211231001), we get a palindrome (121235323532121).

The spelling of 100132112301120 in words is "one hundred trillion, one hundred thirty-two billion, one hundred twelve million, three hundred one thousand, one hundred twenty".