101011130113200 has 120 divisors (see below), whose sum is σ = 332317518116688. Its totient is φ = 26208293207040.

The previous prime is 101011130113183. The next prime is 101011130113259. The reversal of 101011130113200 is 2311031110101.

It is a tau number, because it is divible by the number of its divisors (120).

It is a super-4 number, since 4×101011130113200⁴ (a number of 57 digits) contains 4444 as substring.

It is a Harshad number since it is a multiple of its sum of digits (15).

It is a self number, because there is not a number n which added to its sum of digits gives 101011130113200.

It is an unprimeable number.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 1137468327 + ... + 1137557126.

Almost surely, 2^{101011130113200} is an apocalyptic number.

101011130113200 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

101011130113200 is an abundant number, since it is smaller than the sum of its proper divisors (231306388003488).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

101011130113200 is a wasteful number, since it uses less digits than its factorization.

101011130113200 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2275025511 (or 2275025500 counting only the distinct ones).

The product of its (nonzero) digits is 18, while the sum is 15.

Adding to 101011130113200 its reverse (2311031110101), we get a palindrome (103322161223301).

The spelling of 101011130113200 in words is "one hundred one trillion, eleven billion, one hundred thirty million, one hundred thirteen thousand, two hundred".