101113011132 has 96 divisors (see below), whose sum is σ = 284734195200. Its totient is φ = 27281359872.

The previous prime is 101113011127. The next prime is 101113011149. The reversal of 101113011132 is 231110311101.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 398344 + ... + 600752.

It is an arithmetic number, because the mean of its divisors is an integer number (2965981200).

Almost surely, 2^101113011132 is an apocalyptic number.

101113011132 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 101113011132, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (142367097600).

101113011132 is an abundant number, since it is smaller than the sum of its proper divisors (183621184068).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

101113011132 is a wasteful number, since it uses less digits than its factorization.

101113011132 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 202755 (or 202753 counting only the distinct ones).

The product of its (nonzero) digits is 18, while the sum is 15.

Adding to 101113011132 its reverse (231110311101), we get a palindrome (332223322233).

The spelling of 101113011132 in words is "one hundred one billion, one hundred thirteen million, eleven thousand, one hundred thirty-two".