Search a number
-
+
1011551344000 = 2753411541999
BaseRepresentation
bin11101011100001010010…
…10001001010110000000
310120200222202022111111121
432232011022021112000
5113033124121002000
62052411131522024
7133040120361541
oct16560512112600
93520882274447
101011551344000
1135aaa63a968a
121440665b9314
13745094b4332
1436d606364c8
151b4a5911b1a
hexeb85289580

1011551344000 has 128 divisors (see below), whose sum is σ = 2576311920000. Its totient is φ = 394751488000.

The previous prime is 1011551343997. The next prime is 1011551344043. The reversal of 1011551344000 is 4431551101.

It is a tau number, because it is divible by the number of its divisors (128).

It is a super-2 number, since 2×10115513440002 (a number of 25 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (25).

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 115000 + ... + 1426999.

It is an arithmetic number, because the mean of its divisors is an integer number (20127436875).

Almost surely, 21011551344000 is an apocalyptic number.

1011551344000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 1011551344000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (1288155960000).

1011551344000 is an abundant number, since it is smaller than the sum of its proper divisors (1564760576000).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1011551344000 is an equidigital number, since it uses as much as digits as its factorization.

1011551344000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1542069 (or 1542047 counting only the distinct ones).

The product of its (nonzero) digits is 1200, while the sum is 25.

Adding to 1011551344000 its reverse (4431551101), we get a palindrome (1015982895101).

The spelling of 1011551344000 in words is "one trillion, eleven billion, five hundred fifty-one million, three hundred forty-four thousand".

Divisors: 1 2 4 5 8 10 16 20 25 32 40 41 50 64 80 82 100 125 128 160 164 200 205 250 320 328 400 410 500 640 656 800 820 1000 1025 1312 1600 1640 2000 2050 2624 3200 3280 4000 4100 5125 5248 6560 8000 8200 10250 13120 16000 16400 20500 26240 32800 41000 65600 82000 131200 164000 328000 656000 1541999 3083998 6167996 7709995 12335992 15419990 24671984 30839980 38549975 49343968 61679960 63221959 77099950 98687936 123359920 126443918 154199900 192749875 197375872 246719840 252887836 308399800 316109795 385499750 493439680 505775672 616799600 632219590 770999500 986879360 1011551344 1233599200 1264439180 1541999000 1580548975 2023102688 2467198400 2528878360 3083998000 3161097950 4046205376 4934396800 5057756720 6167996000 6322195900 7902744875 8092410752 10115513440 12335992000 12644391800 15805489750 20231026880 24671984000 25288783600 31610979500 40462053760 50577567200 63221959000 101155134400 126443918000 202310268800 252887836000 505775672000 1011551344000