Base | Representation |
---|---|
bin | 1001010010011110111000… |
… | …1011101110010001101010 |
3 | 1100011100212211011101000121 |
4 | 2110213232023232101222 |
5 | 2314312444112010010 |
6 | 33415503151353454 |
7 | 2102605651536046 |
oct | 224475613562152 |
9 | 40140784141017 |
10 | 10213133313130 |
11 | 3288402554810 |
12 | 118b45982288a |
13 | 59112c354ba7 |
14 | 27446555d026 |
15 | 12aa0139e3da |
hex | 949ee2ee46a |
10213133313130 has 64 divisors (see below), whose sum is σ = 21559557611520. Its totient is φ = 3443540385600.
The previous prime is 10213133313067. The next prime is 10213133313217. The reversal of 10213133313130 is 3131333131201.
It is a junction number, because it is equal to n+sod(n) for n = 10213133313095 and 10213133313104.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 51887586 + ... + 52084045.
It is an arithmetic number, because the mean of its divisors is an integer number (336868087680).
Almost surely, 210213133313130 is an apocalyptic number.
10213133313130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
10213133313130 is an abundant number, since it is smaller than the sum of its proper divisors (11346424298390).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
10213133313130 is a wasteful number, since it uses less digits than its factorization.
10213133313130 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 103971715.
The product of its (nonzero) digits is 1458, while the sum is 25.
Adding to 10213133313130 its reverse (3131333131201), we get a palindrome (13344466444331).
The spelling of 10213133313130 in words is "ten trillion, two hundred thirteen billion, one hundred thirty-three million, three hundred thirteen thousand, one hundred thirty".
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