Base | Representation |
---|---|
bin | 11110000000111100101… |
… | …01100010010100100000 |
3 | 10122120222010222201111222 |
4 | 33000132111202110200 |
5 | 113344101041104440 |
6 | 2105435001554212 |
7 | 134336413552415 |
oct | 17003625422440 |
9 | 3576863881458 |
10 | 1031301113120 |
11 | 368410657523 |
12 | 147a587a5968 |
13 | 76336098455 |
14 | 37cb55c210c |
15 | 1bc5e7002b5 |
hex | f01e562520 |
1031301113120 has 96 divisors (see below), whose sum is σ = 2603880131328. Its totient is φ = 384625881088.
The previous prime is 1031301113093. The next prime is 1031301113197. The reversal of 1031301113120 is 213111031301.
It is a super-2 number, since 2×10313011131202 (a number of 25 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (17).
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1480712 + ... + 2062791.
It is an arithmetic number, because the mean of its divisors is an integer number (27123751368).
Almost surely, 21031301113120 is an apocalyptic number.
1031301113120 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
1031301113120 is an abundant number, since it is smaller than the sum of its proper divisors (1572579018208).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1031301113120 is a wasteful number, since it uses less digits than its factorization.
1031301113120 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3543642 (or 3543634 counting only the distinct ones).
The product of its (nonzero) digits is 54, while the sum is 17.
Adding to 1031301113120 its reverse (213111031301), we get a palindrome (1244412144421).
The spelling of 1031301113120 in words is "one trillion, thirty-one billion, three hundred one million, one hundred thirteen thousand, one hundred twenty".
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