11000303320110 has 96 divisors (see below), whose sum is σ = 28603058305248. Its totient is φ = 2706318950400.

The previous prime is 11000303320067. The next prime is 11000303320163. The reversal of 11000303320110 is 1102330300011.

It is a super-4 number, since 4×11000303320110⁴ (a number of 53 digits) contains 4444 as substring. Note that it is a super-d number also for d = 3.

It is a Harshad number since it is a multiple of its sum of digits (15).

It is a self number, because there is not a number n which added to its sum of digits gives 11000303320110.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 8916910 + ... + 10075310.

It is an arithmetic number, because the mean of its divisors is an integer number (297948524013).

Almost surely, 2^{11000303320110} is an apocalyptic number.

11000303320110 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is a practical number, because each smaller number is the sum of distinct divisors of 11000303320110, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (14301529152624).

11000303320110 is an abundant number, since it is smaller than the sum of its proper divisors (17602754985138).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

11000303320110 is a wasteful number, since it uses less digits than its factorization.

11000303320110 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1160310 (or 1160297 counting only the distinct ones).

The product of its (nonzero) digits is 54, while the sum is 15.

Adding to 11000303320110 its reverse (1102330300011), we get a palindrome (12102633620121).

The spelling of 11000303320110 in words is "eleven trillion, three hundred three million, three hundred twenty thousand, one hundred ten".