11003444130 has 128 divisors (see below), whose sum is σ = 30743032320. Its totient is φ = 2468413440.

The previous prime is 11003444119. The next prime is 11003444143. The reversal of 11003444130 is 3144430011.

It is a Harshad number since it is a multiple of its sum of digits (21).

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 11003444097 and 11003444106.

It is an unprimeable number.

It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 9850332 + ... + 9851448.

It is an arithmetic number, because the mean of its divisors is an integer number (240179940).

Almost surely, 2^11003444130 is an apocalyptic number.

11003444130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is a practical number, because each smaller number is the sum of distinct divisors of 11003444130, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (15371516160).

11003444130 is an abundant number, since it is smaller than the sum of its proper divisors (19739588190).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

11003444130 is a wasteful number, since it uses less digits than its factorization.

11003444130 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1964.

The product of its (nonzero) digits is 576, while the sum is 21.

Adding to 11003444130 its reverse (3144430011), we get a palindrome (14147874141).

The spelling of 11003444130 in words is "eleven billion, three million, four hundred forty-four thousand, one hundred thirty".