Base | Representation |
---|---|
bin | 10000000001101011010… |
… | …000111001110111010000 |
3 | 10220021200021100201001220 |
4 | 100001223100321313100 |
5 | 121020441133034300 |
6 | 2201534013325040 |
7 | 142365342631611 |
oct | 20015320716720 |
9 | 3807607321056 |
10 | 1101311221200 |
11 | 395077522983 |
12 | 159536a96780 |
13 | 7cb126418c8 |
14 | 3b4376a9c08 |
15 | 1d9aab5ada0 |
hex | 1006b439dd0 |
1101311221200 has 120 divisors (see below), whose sum is σ = 3529158994368. Its totient is φ = 293575434240.
The previous prime is 1101311221189. The next prime is 1101311221321. The reversal of 1101311221200 is 21221131011.
It is a tau number, because it is divible by the number of its divisors (120).
It is a Harshad number since it is a multiple of its sum of digits (15).
It is a self number, because there is not a number n which added to its sum of digits gives 1101311221200.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 3136917 + ... + 3470283.
Almost surely, 21101311221200 is an apocalyptic number.
1101311221200 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 1101311221200, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (1764579497184).
1101311221200 is an abundant number, since it is smaller than the sum of its proper divisors (2427847773168).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1101311221200 is a wasteful number, since it uses less digits than its factorization.
1101311221200 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 336141 (or 336130 counting only the distinct ones).
The product of its (nonzero) digits is 24, while the sum is 15.
Adding to 1101311221200 its reverse (21221131011), we get a palindrome (1122532352211).
It can be divided in two parts, 110131 and 1221200, that added together give a palindrome (1331331).
The spelling of 1101311221200 in words is "one trillion, one hundred one billion, three hundred eleven million, two hundred twenty-one thousand, two hundred".
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