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1102012301120 = 2658378752721
BaseRepresentation
bin10000000010010101000…
…011010011111101000000
310220100111010120020220212
4100002111003103331000
5121023410122113440
62202131340053252
7142421615001443
oct20022503237500
93810433506825
101102012301120
113953a723a675
121596b1834228
137cbc496b6b3
143b4a284565a
151d9ec493465
hex100950d3f40

1102012301120 has 112 divisors (see below), whose sum is σ = 2659208263488. Its totient is φ = 434932408320.

The previous prime is 1102012301101. The next prime is 1102012301129. The reversal of 1102012301120 is 211032102011.

It is a super-2 number, since 2×11020123011202 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1102012301095 and 1102012301104.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1102012301129) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 20876360 + ... + 20929080.

It is an arithmetic number, because the mean of its divisors is an integer number (23742930924).

Almost surely, 21102012301120 is an apocalyptic number.

1102012301120 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 1102012301120, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (1329604131744).

1102012301120 is an abundant number, since it is smaller than the sum of its proper divisors (1557195962368).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1102012301120 is an equidigital number, since it uses as much as digits as its factorization.

1102012301120 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 53608 (or 53598 counting only the distinct ones).

The product of its (nonzero) digits is 24, while the sum is 14.

Adding to 1102012301120 its reverse (211032102011), we get a palindrome (1313044403131).

The spelling of 1102012301120 in words is "one trillion, one hundred two billion, twelve million, three hundred one thousand, one hundred twenty".

Divisors: 1 2 4 5 8 10 16 20 32 40 64 80 83 160 166 320 332 415 664 787 830 1328 1574 1660 2656 3148 3320 3935 5312 6296 6640 7870 12592 13280 15740 25184 26560 31480 50368 52721 62960 65321 105442 125920 130642 210884 251840 261284 263605 326605 421768 522568 527210 653210 843536 1045136 1054420 1306420 1687072 2090272 2108840 2612840 3374144 4180544 4217680 4375843 5225680 8435360 8751686 10451360 16870720 17503372 20902720 21879215 35006744 41491427 43758430 70013488 82982854 87516860 140026976 165965708 175033720 207457135 280053952 331931416 350067440 414914270 663862832 700134880 829828540 1327725664 1400269760 1659657080 2655451328 3319314160 3443788441 6638628320 6887576882 13277256640 13775153764 17218942205 27550307528 34437884410 55100615056 68875768820 110201230112 137751537640 220402460224 275503075280 551006150560 1102012301120