Base | Representation |
---|---|
bin | 1010000011110101011110… |
… | …1000110101100100000111 |
3 | 1110011102101212211012102202 |
4 | 2200331113220311210013 |
5 | 2422210422321011101 |
6 | 35305205223225115 |
7 | 2221063111104122 |
oct | 240752750654407 |
9 | 43142355735382 |
10 | 11061011110151 |
11 | 3584a48458aa2 |
12 | 12a78462a819b |
13 | 6230834ab372 |
14 | 2a34da4293b9 |
15 | 142ac7a8536b |
hex | a0f57a35907 |
11061011110151 has 2 divisors, whose sum is σ = 11061011110152. Its totient is φ = 11061011110150.
The previous prime is 11061011110129. The next prime is 11061011110153. The reversal of 11061011110151 is 15101111016011.
It is a happy number.
11061011110151 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11061011110151 - 226 = 11060944001287 is a prime.
Together with 11061011110153, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11061011110153) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5530505555075 + 5530505555076.
It is an arithmetic number, because the mean of its divisors is an integer number (5530505555076).
Almost surely, 211061011110151 is an apocalyptic number.
11061011110151 is a deficient number, since it is larger than the sum of its proper divisors (1).
11061011110151 is an equidigital number, since it uses as much as digits as its factorization.
11061011110151 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 30, while the sum is 20.
Adding to 11061011110151 its reverse (15101111016011), we get a palindrome (26162122126162).
The spelling of 11061011110151 in words is "eleven trillion, sixty-one billion, eleven million, one hundred ten thousand, one hundred fifty-one".
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