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1121243310 = 23551141947
BaseRepresentation
bin100001011010100…
…1101000010101110
32220010211001200000
41002311031002232
54244014241220
6303132045130
736533260635
oct10265150256
92803731600
101121243310
11525a04770
122736037a6
1314b3aaca5
14a8cac51c
1568680390
hex42d4d0ae

1121243310 has 96 divisors (see below), whose sum is σ = 3298119552. Its totient is φ = 271810080.

The previous prime is 1121243293. The next prime is 1121243339. The reversal of 1121243310 is 133421211.

1121243310 is a `hidden beast` number, since 11 + 212 + 433 + 10 = 666.

It is a super-2 number, since 2×11212433102 = 2514373120439512200, which contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 5757 + ... + 47703.

It is an arithmetic number, because the mean of its divisors is an integer number (34355412).

Almost surely, 21121243310 is an apocalyptic number.

1121243310 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is a practical number, because each smaller number is the sum of distinct divisors of 1121243310, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (1649059776).

1121243310 is an abundant number, since it is smaller than the sum of its proper divisors (2176876242).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1121243310 is a wasteful number, since it uses less digits than its factorization.

1121243310 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 41980 (or 41968 counting only the distinct ones).

The product of its (nonzero) digits is 144, while the sum is 18.

The square root of 1121243310 is about 33484.9714050946. The cubic root of 1121243310 is about 1038.8829568242.

Adding to 1121243310 its reverse (133421211), we get a palindrome (1254664521).

The spelling of 1121243310 in words is "one billion, one hundred twenty-one million, two hundred forty-three thousand, three hundred ten".

Divisors: 1 2 3 5 6 9 10 11 15 18 22 27 30 33 45 54 55 66 81 90 99 110 135 162 165 198 243 270 297 330 405 486 495 594 810 891 990 1215 1485 1782 2430 2673 2970 4455 5346 8910 13365 26730 41947 83894 125841 209735 251682 377523 419470 461417 629205 755046 922834 1132569 1258410 1384251 1887615 2265138 2307085 2768502 3397707 3775230 4152753 4614170 5662845 6795414 6921255 8305506 10193121 11325690 12458259 13842510 16988535 20386242 20763765 24916518 33977070 37374777 41527530 50965605 62291295 74749554 101931210 112124331 124582590 186873885 224248662 373747770 560621655 1121243310