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1121314012440 = 233537966126141
BaseRepresentation
bin10000010100010011100…
…001011111110100011000
310222012022022010210011220
4100110103201133310120
5121332422341344230
62215042522452040
7144004130562336
oct20242341376430
93865268123156
101121314012440
113a2601589006
12161399964020
138197c785b5b
143c3b40bab56
151e27bc78d10
hex1051385fd18

1121314012440 has 128 divisors (see below), whose sum is σ = 3455349174720. Its totient is φ = 290894284800.

The previous prime is 1121314012433. The next prime is 1121314012453. The reversal of 1121314012440 is 442104131211.

It is a happy number.

It is a super-2 number, since 2×11213140124402 (a number of 25 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (24).

It is a self number, because there is not a number n which added to its sum of digits gives 1121314012440.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 42881770 + ... + 42907910.

Almost surely, 21121314012440 is an apocalyptic number.

1121314012440 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 1121314012440, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (1727674587360).

1121314012440 is an abundant number, since it is smaller than the sum of its proper divisors (2334035162280).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1121314012440 is a wasteful number, since it uses less digits than its factorization.

1121314012440 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 35853 (or 35849 counting only the distinct ones).

The product of its (nonzero) digits is 768, while the sum is 24.

Adding to 1121314012440 its reverse (442104131211), we get a palindrome (1563418143651).

The spelling of 1121314012440 in words is "one trillion, one hundred twenty-one billion, three hundred fourteen million, twelve thousand, four hundred forty".

Divisors: 1 2 3 4 5 6 8 10 12 15 20 24 30 37 40 60 74 111 120 148 185 222 296 370 444 555 740 888 1110 1480 2220 4440 9661 19322 26141 28983 38644 48305 52282 57966 77288 78423 96610 104564 115932 130705 144915 156846 193220 209128 231864 261410 289830 313692 357457 386440 392115 522820 579660 627384 714914 784230 967217 1045640 1072371 1159320 1429828 1568460 1787285 1934434 2144742 2859656 2901651 3136920 3574570 3868868 4289484 4836085 5361855 5803302 7149140 7737736 8578968 9672170 10723710 11606604 14298280 14508255 19344340 21447420 23213208 29016510 38688680 42894840 58033020 116066040 252548201 505096402 757644603 1010192804 1262741005 1515289206 2020385608 2525482010 3030578412 3788223015 5050964020 6061156824 7576446030 9344283437 10101928040 15152892060 18688566874 28032850311 30305784120 37377133748 46721417185 56065700622 74754267496 93442834370 112131401244 140164251555 186885668740 224262802488 280328503110 373771337480 560657006220 1121314012440