Base | Representation |
---|---|
bin | 110100001101110011… |
… | …0000101110111000000 |
3 | 101201102200100220011111 |
4 | 1220123212011313000 |
5 | 3314121310320000 |
6 | 123302432253104 |
7 | 11046511202515 |
oct | 1503346056700 |
9 | 351380326144 |
10 | 112132120000 |
11 | 4361172745a |
12 | 198949a1194 |
13 | a760152984 |
14 | 55da43130c |
15 | 2db43a6cba |
hex | 1a1b985dc0 |
112132120000 has 70 divisors (see below), whose sum is σ = 278051313848. Its totient is φ = 44852832000.
The previous prime is 112132119997. The next prime is 112132120039. The reversal of 112132120000 is 21231211.
It is a super-2 number, since 2×1121321200002 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 9 ways as a sum of consecutive naturals, for example, 1361652 + ... + 1441651.
Almost surely, 2112132120000 is an apocalyptic number.
112132120000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
112132120000 is an abundant number, since it is smaller than the sum of its proper divisors (165919193848).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
112132120000 is an frugal number, since it uses more digits than its factorization.
112132120000 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2803335 (or 2803310 counting only the distinct ones).
The product of its (nonzero) digits is 24, while the sum is 13.
Adding to 112132120000 its reverse (21231211), we get a palindrome (112153351211).
The spelling of 112132120000 in words is "one hundred twelve billion, one hundred thirty-two million, one hundred twenty thousand".
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