Base | Representation |
---|---|
bin | 1010010010010110010001… |
… | …0100111011110110100000 |
3 | 1111001020221111020202201220 |
4 | 2210211210110323312200 |
5 | 2440302030004200000 |
6 | 40015521141255040 |
7 | 2245100400413343 |
oct | 244454424736640 |
9 | 44036844222656 |
10 | 11310332100000 |
11 | 367075967992a |
12 | 1328027404480 |
13 | 6407379999ab |
14 | 2b15cc9a845a |
15 | 14931ae761a0 |
hex | a496453bda0 |
11310332100000 has 144 divisors (see below), whose sum is σ = 37109653017696. Its totient is φ = 3016088480000.
The previous prime is 11310332099999. The next prime is 11310332100019. The reversal of 11310332100000 is 123301311.
It is a super-2 number, since 2×113103321000002 (a number of 27 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (15).
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 18550554 + ... + 19150553.
It is an arithmetic number, because the mean of its divisors is an integer number (257705923734).
Almost surely, 211310332100000 is an apocalyptic number.
11310332100000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
11310332100000 is an abundant number, since it is smaller than the sum of its proper divisors (25799320917696).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
11310332100000 is an frugal number, since it uses more digits than its factorization.
11310332100000 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 37701145 (or 37701117 counting only the distinct ones).
The product of its (nonzero) digits is 54, while the sum is 15.
Adding to 11310332100000 its reverse (123301311), we get a palindrome (11310455401311).
The spelling of 11310332100000 in words is "eleven trillion, three hundred ten billion, three hundred thirty-two million, one hundred thousand".
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