Base | Representation |
---|---|
bin | 11001101110001101010101… |
… | …000110101001001010000110 |
3 | 112211112210110021021002120220 |
4 | 121232031111012221022012 |
5 | 104311431204240223100 |
6 | 1040333343544005210 |
7 | 32554060620165120 |
oct | 3156152506511206 |
9 | 484483407232526 |
10 | 113126571414150 |
11 | 330557893a5778 |
12 | 1083082ba60806 |
13 | 4b17a36581958 |
14 | 1dd14d8c14210 |
15 | d12a35cb7aa0 |
hex | 66e3551a9286 |
113126571414150 has 96 divisors (see below), whose sum is σ = 320639414692608. Its totient is φ = 25856986761600.
The previous prime is 113126571414133. The next prime is 113126571414173. The reversal of 113126571414150 is 51414175621311.
It is a Harshad number since it is a multiple of its sum of digits (42).
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 52935865 + ... + 55031435.
It is an arithmetic number, because the mean of its divisors is an integer number (3339993903048).
Almost surely, 2113126571414150 is an apocalyptic number.
113126571414150 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
113126571414150 is an abundant number, since it is smaller than the sum of its proper divisors (207512843278458).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
113126571414150 is a wasteful number, since it uses less digits than its factorization.
113126571414150 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2147006 (or 2147001 counting only the distinct ones).
The product of its (nonzero) digits is 100800, while the sum is 42.
The spelling of 113126571414150 in words is "one hundred thirteen trillion, one hundred twenty-six billion, five hundred seventy-one million, four hundred fourteen thousand, one hundred fifty".
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