113140104120 has 96 divisors (see below), whose sum is σ = 372742484400. Its totient is φ = 29757390336.

The previous prime is 113140104107. The next prime is 113140104169. The reversal of 113140104120 is 21401041311.

113140104120 is a `hidden beast` number, since 113 + 140 + 1 + 0 + 412 + 0 = 666.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is a junction number, because it is equal to n+sod(n) for n = 113140104093 and 113140104102.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 2126310 + ... + 2178869.

Almost surely, 2^113140104120 is an apocalyptic number.

113140104120 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

113140104120 is an abundant number, since it is smaller than the sum of its proper divisors (259602380280).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

113140104120 is a wasteful number, since it uses less digits than its factorization.

113140104120 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4305269 (or 4305262 counting only the distinct ones).

The product of its (nonzero) digits is 96, while the sum is 18.

Adding to 113140104120 its reverse (21401041311), we get a palindrome (134541145431).

The spelling of 113140104120 in words is "one hundred thirteen billion, one hundred forty million, one hundred four thousand, one hundred twenty".