Base | Representation |
---|---|
bin | 11001101111110000101000… |
… | …101010110110011010011110 |
3 | 112211220222200101222020121220 |
4 | 121233300220222312122132 |
5 | 104320203043212111220 |
6 | 1040454340343034210 |
7 | 32564554154161134 |
oct | 3157605052663236 |
9 | 484828611866556 |
10 | 113233200113310 |
11 | 33096a26531642 |
12 | 1084942973b966 |
13 | 4b24aca493894 |
14 | 1dd673237b754 |
15 | d156c6e26540 |
hex | 66fc28ab669e |
113233200113310 has 32 divisors (see below), whose sum is σ = 271760250908160. Its totient is φ = 30195456626208.
The previous prime is 113233200113263. The next prime is 113233200113347. The reversal of 113233200113310 is 13311002332311.
It is a super-3 number, since 3×1132332001133103 (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 11559279 + ... + 18975861.
It is an arithmetic number, because the mean of its divisors is an integer number (8492507840880).
Almost surely, 2113233200113310 is an apocalyptic number.
113233200113310 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
113233200113310 is an abundant number, since it is smaller than the sum of its proper divisors (158527050794850).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
113233200113310 is a wasteful number, since it uses less digits than its factorization.
113233200113310 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 7925512.
The product of its (nonzero) digits is 972, while the sum is 24.
Adding to 113233200113310 its reverse (13311002332311), we get a palindrome (126544202445621).
The spelling of 113233200113310 in words is "one hundred thirteen trillion, two hundred thirty-three billion, two hundred million, one hundred thirteen thousand, three hundred ten".
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