Base | Representation |
---|---|
bin | 110100101111001001… |
… | …1011011100000011000 |
3 | 101211022200022012102110 |
4 | 1221132103123200120 |
5 | 3323414313121100 |
6 | 124005452232320 |
7 | 11116321115166 |
oct | 1513623334030 |
9 | 354280265373 |
10 | 113251301400 |
11 | 44036452a66 |
12 | 19b4776b6a0 |
13 | a8aac8b2a3 |
14 | 56a4d24236 |
15 | 2e2c77b250 |
hex | 1a5e4db818 |
113251301400 has 96 divisors (see below), whose sum is σ = 353108716560. Its totient is φ = 30025751040.
The previous prime is 113251301393. The next prime is 113251301407. The reversal of 113251301400 is 4103152311.
113251301400 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is an interprime number because it is at equal distance from previous prime (113251301393) and next prime (113251301407).
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (113251301407) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 441727 + ... + 649326.
Almost surely, 2113251301400 is an apocalyptic number.
113251301400 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
113251301400 is an abundant number, since it is smaller than the sum of its proper divisors (239857415160).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
113251301400 is a wasteful number, since it uses less digits than its factorization.
113251301400 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1091245 (or 1091236 counting only the distinct ones).
The product of its (nonzero) digits is 360, while the sum is 21.
Adding to 113251301400 its reverse (4103152311), we get a palindrome (117354453711).
The spelling of 113251301400 in words is "one hundred thirteen billion, two hundred fifty-one million, three hundred one thousand, four hundred".
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