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11334014012000 = 25536474379449
BaseRepresentation
bin1010010011101110011111…
…1000010000101001100000
31111010112001220221112201202
42210323213320100221200
52441144030041341000
640034435115020332
72246566301350511
oct244734770205140
944115056845652
1011334014012000
11367a801483929
12133073643a6a8
13642a40104184
142b27d7c82a08
15149c55083dd5
hexa4ee7e10a60

11334014012000 has 96 divisors (see below), whose sum is σ = 27890720020800. Its totient is φ = 4526597452800.

The previous prime is 11334014011951. The next prime is 11334014012011. The reversal of 11334014012000 is 21041043311.

It is a super-2 number, since 2×113340140120002 (a number of 27 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (20).

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 398276 + ... + 4777724.

It is an arithmetic number, because the mean of its divisors is an integer number (290528333550).

Almost surely, 211334014012000 is an apocalyptic number.

11334014012000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 11334014012000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (13945360010400).

11334014012000 is an abundant number, since it is smaller than the sum of its proper divisors (16556706008800).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

11334014012000 is an equidigital number, since it uses as much as digits as its factorization.

11334014012000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4380121 (or 4380103 counting only the distinct ones).

The product of its (nonzero) digits is 288, while the sum is 20.

Adding to 11334014012000 its reverse (21041043311), we get a palindrome (11355055055311).

The spelling of 11334014012000 in words is "eleven trillion, three hundred thirty-four billion, fourteen million, twelve thousand".

Divisors: 1 2 4 5 8 10 16 20 25 32 40 50 80 100 125 160 200 250 400 500 647 800 1000 1294 2000 2588 3235 4000 5176 6470 10352 12940 16175 20704 25880 32350 51760 64700 80875 103520 129400 161750 258800 323500 517600 647000 1294000 2588000 4379449 8758898 17517796 21897245 35035592 43794490 70071184 87588980 109486225 140142368 175177960 218972450 350355920 437944900 547431125 700711840 875889800 1094862250 1751779600 2189724500 2833503503 3503559200 4379449000 5667007006 8758898000 11334014012 14167517515 17517796000 22668028024 28335035030 45336056048 56670070060 70837587575 90672112096 113340140120 141675175150 226680280240 283350350300 354187937875 453360560480 566700700600 708375875750 1133401401200 1416751751500 2266802802400 2833503503000 5667007006000 11334014012000