Base | Representation |
---|---|
bin | 1010010100001001101100… |
… | …0000110100010011000010 |
3 | 1111011012220200210211202020 |
4 | 2211002123000310103002 |
5 | 2441304002433003010 |
6 | 40042043342302310 |
7 | 2250245225221611 |
oct | 245023300642302 |
9 | 44135820724666 |
10 | 11341314344130 |
11 | 3682908309471 |
12 | 1332033287996 |
13 | 6436346c3124 |
14 | 2b2ccb65b878 |
15 | 14a030e25470 |
hex | a509b0344c2 |
11341314344130 has 128 divisors (see below), whose sum is σ = 31383247046400. Its totient is φ = 2603647033344.
The previous prime is 11341314344117. The next prime is 11341314344153. The reversal of 11341314344130 is 3144341314311.
It is a super-2 number, since 2×113413143441302 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 11341314344091 and 11341314344100.
It is an unprimeable number.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 19898547 + ... + 20460566.
It is an arithmetic number, because the mean of its divisors is an integer number (245181617550).
Almost surely, 211341314344130 is an apocalyptic number.
11341314344130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
11341314344130 is an abundant number, since it is smaller than the sum of its proper divisors (20041932702270).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
11341314344130 is a wasteful number, since it uses less digits than its factorization.
11341314344130 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 40359188.
The product of its (nonzero) digits is 20736, while the sum is 33.
Adding to 11341314344130 its reverse (3144341314311), we get a palindrome (14485655658441).
The spelling of 11341314344130 in words is "eleven trillion, three hundred forty-one billion, three hundred fourteen million, three hundred forty-four thousand, one hundred thirty".
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