Base | Representation |
---|---|
bin | 110100110100100110… |
… | …1111001111000010000 |
3 | 101211210102211200200000 |
4 | 1221221031321320100 |
5 | 3324303201333240 |
6 | 124035552530000 |
7 | 11124003340131 |
oct | 1515115717020 |
9 | 354712750600 |
10 | 113434402320 |
11 | 4411a843438 |
12 | 19b98b50900 |
13 | a909ba9725 |
14 | 56c1387c88 |
15 | 2e3d898430 |
hex | 1a69379e10 |
113434402320 has 120 divisors (see below), whose sum is σ = 395059881216. Its totient is φ = 30249168768.
The previous prime is 113434402313. The next prime is 113434402349. The reversal of 113434402320 is 23204434311.
It is a tau number, because it is divible by the number of its divisors (120).
It is a Harshad number since it is a multiple of its sum of digits (27).
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 2898112 + ... + 2936991.
Almost surely, 2113434402320 is an apocalyptic number.
113434402320 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
113434402320 is an abundant number, since it is smaller than the sum of its proper divisors (281625478896).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
113434402320 is an equidigital number, since it uses as much as digits as its factorization.
113434402320 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5835131 (or 5835113 counting only the distinct ones).
The product of its (nonzero) digits is 6912, while the sum is 27.
Adding to 113434402320 its reverse (23204434311), we get a palindrome (136638836631).
The spelling of 113434402320 in words is "one hundred thirteen billion, four hundred thirty-four million, four hundred two thousand, three hundred twenty".
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