1143314040 has 128 divisors (see below), whose sum is σ = 3752179200. Its totient is φ = 276395520.

The previous prime is 1143314027. The next prime is 1143314119. The reversal of 1143314040 is 404133411.

It is a super-2 number, since 2×1143314040² = 2614333988122243200, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1143313998 and 1143314016.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 578494 + ... + 580466.

It is an arithmetic number, because the mean of its divisors is an integer number (29313900).

Almost surely, 2^1143314040 is an apocalyptic number.

1143314040 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 1143314040, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (1876089600).

1143314040 is an abundant number, since it is smaller than the sum of its proper divisors (2608865160).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1143314040 is a wasteful number, since it uses less digits than its factorization.

1143314040 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2437 (or 2433 counting only the distinct ones).

The product of its (nonzero) digits is 576, while the sum is 21.

The square root of 1143314040 is about 33812.9271137534. The cubic root of 1143314040 is about 1045.6552257802.

Adding to 1143314040 its reverse (404133411), we get a palindrome (1547447451).

The spelling of 1143314040 in words is "one billion, one hundred forty-three million, three hundred fourteen thousand, forty".