Base | Representation |
---|---|
bin | 10101011110100111… |
… | …11110100000010110 |
3 | 1002202121221211220110 |
4 | 22233103332200112 |
5 | 142103440343100 |
6 | 5144121143450 |
7 | 555516306453 |
oct | 125723764026 |
9 | 32677854813 |
10 | 11531184150 |
11 | 4988064362 |
12 | 229992ab86 |
13 | 1119caa6b5 |
14 | 7b566282a |
15 | 477517250 |
hex | 2af4fe816 |
11531184150 has 48 divisors (see below), whose sum is σ = 30279539664. Its totient is φ = 2894100480.
The previous prime is 11531184103. The next prime is 11531184179. The reversal of 11531184150 is 5148113511.
It is a super-2 number, since 2×115311841502 (a number of 21 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (30).
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 2258467 + ... + 2263566.
It is an arithmetic number, because the mean of its divisors is an integer number (630823743).
Almost surely, 211531184150 is an apocalyptic number.
11531184150 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
11531184150 is an abundant number, since it is smaller than the sum of its proper divisors (18748355514).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
11531184150 is a wasteful number, since it uses less digits than its factorization.
11531184150 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4522065 (or 4522060 counting only the distinct ones).
The product of its (nonzero) digits is 2400, while the sum is 30.
Adding to 11531184150 its reverse (5148113511), we get a palindrome (16679297661).
The spelling of 11531184150 in words is "eleven billion, five hundred thirty-one million, one hundred eighty-four thousand, one hundred fifty".
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