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120021211320 = 23351000176761
BaseRepresentation
bin110111111000111010…
…0100101100010111000
3102110210111002020221220
41233301310211202320
53431300412230240
6131045331032040
711446144314663
oct1576164454270
9373714066856
10120021211320
114699a93253a
121b316a3b620
13b419702c4a
145b480a86da
1531c6c955d0
hex1bf1d258b8

120021211320 has 32 divisors (see below), whose sum is σ = 360063634320. Its totient is φ = 32005656320.

The previous prime is 120021211313. The next prime is 120021211327. The reversal of 120021211320 is 23112120021.

120021211320 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is an interprime number because it is at equal distance from previous prime (120021211313) and next prime (120021211327).

It is a super-2 number, since 2×1200212113202 (a number of 23 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (15).

It is a self number, because there is not a number n which added to its sum of digits gives 120021211320.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (120021211327) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 500088261 + ... + 500088500.

Almost surely, 2120021211320 is an apocalyptic number.

120021211320 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

120021211320 is an abundant number, since it is smaller than the sum of its proper divisors (240042423000).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

120021211320 is a wasteful number, since it uses less digits than its factorization.

120021211320 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1000176775 (or 1000176771 counting only the distinct ones).

The product of its (nonzero) digits is 48, while the sum is 15.

Adding to 120021211320 its reverse (23112120021), we get a palindrome (143133331341).

The spelling of 120021211320 in words is "one hundred twenty billion, twenty-one million, two hundred eleven thousand, three hundred twenty".

Divisors: 1 2 3 4 5 6 8 10 12 15 20 24 30 40 60 120 1000176761 2000353522 3000530283 4000707044 5000883805 6001060566 8001414088 10001767610 12002121132 15002651415 20003535220 24004242264 30005302830 40007070440 60010605660 120021211320