Base | Representation |
---|---|
bin | 100011110100000… |
… | …1000110111110110 |
3 | 10002202012220120210 |
4 | 1013220020313312 |
5 | 4430114020223 |
6 | 315124410250 |
7 | 41531214324 |
oct | 10750106766 |
9 | 3082186523 |
10 | 1201704438 |
11 | 567370370 |
12 | 296546986 |
13 | 161c7021c |
14 | b5854d14 |
15 | 70775893 |
hex | 47a08df6 |
1201704438 has 64 divisors (see below), whose sum is σ = 2765537280. Its totient is φ = 344282400.
The previous prime is 1201704409. The next prime is 1201704451. The reversal of 1201704438 is 8344071021.
1201704438 is digitally balanced in base 4, because in such base it contains all the possibile digits an equal number of times.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 1212123 + ... + 1213113.
It is an arithmetic number, because the mean of its divisors is an integer number (43211520).
Almost surely, 21201704438 is an apocalyptic number.
It is a practical number, because each smaller number is the sum of distinct divisors of 1201704438, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (1382768640).
1201704438 is an abundant number, since it is smaller than the sum of its proper divisors (1563832842).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1201704438 is a wasteful number, since it uses less digits than its factorization.
1201704438 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1993.
The product of its (nonzero) digits is 5376, while the sum is 30.
The square root of 1201704438 is about 34665.6088652716. The cubic root of 1201704438 is about 1063.1614521781.
Adding to 1201704438 its reverse (8344071021), we get a palindrome (9545775459).
The spelling of 1201704438 in words is "one billion, two hundred one million, seven hundred four thousand, four hundred thirty-eight".
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