Search a number
-
+
12100300301310 = 2351361508629689
BaseRepresentation
bin1011000000010101001000…
…0110011110001111111110
31120211202222201210022222220
42300011102012132033332
53041222403334120220
641422445021350210
72356134502344024
oct260052206361776
946752881708886
1012100300301310
11394578807a801
121435152108366
1369a0904a42c0
142db92c890714
1515eb536c8540
hexb015219e3fe

12100300301310 has 64 divisors (see below), whose sum is σ = 31787321106240. Its totient is φ = 2929707002880.

The previous prime is 12100300301251. The next prime is 12100300301311. The reversal of 12100300301310 is 1310300300121.

12100300301310 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a super-2 number, since 2×121003003013102 (a number of 27 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (15).

It is a Curzon number.

It is a self number, because there is not a number n which added to its sum of digits gives 12100300301310.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12100300301311) by changing a digit.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 254291055 + ... + 254338634.

It is an arithmetic number, because the mean of its divisors is an integer number (496676892285).

Almost surely, 212100300301310 is an apocalyptic number.

12100300301310 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

12100300301310 is an abundant number, since it is smaller than the sum of its proper divisors (19687020804930).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

12100300301310 is a wasteful number, since it uses less digits than its factorization.

12100300301310 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 508629773.

The product of its (nonzero) digits is 54, while the sum is 15.

Adding to 12100300301310 its reverse (1310300300121), we get a palindrome (13410600601431).

The spelling of 12100300301310 in words is "twelve trillion, one hundred billion, three hundred million, three hundred one thousand, three hundred ten".

Divisors: 1 2 3 5 6 10 13 15 26 30 39 61 65 78 122 130 183 195 305 366 390 610 793 915 1586 1830 2379 3965 4758 7930 11895 23790 508629689 1017259378 1525889067 2543148445 3051778134 5086296890 6612185957 7629445335 13224371914 15258890670 19836557871 31026411029 33060929785 39673115742 62052822058 66121859570 93079233087 99182789355 155132055145 186158466174 198365578710 310264110290 403343343377 465396165435 806686686754 930792330870 1210030030131 2016716716885 2420060060262 4033433433770 6050150150655 12100300301310