Base | Representation |
---|---|
bin | 1011000000011011110101… |
… | …1100000011010001110000 |
3 | 1120211221122020100101222120 |
4 | 2300012331130003101300 |
5 | 3041240100341320422 |
6 | 41423343431234240 |
7 | 2356230230141433 |
oct | 260067534032160 |
9 | 46757566311876 |
10 | 12102101120112 |
11 | 3946521643603 |
12 | 1435575218980 |
13 | 69a2b95bcc63 |
14 | 2dba5dadb81a |
15 | 15ec0b84445c |
hex | b01bd703470 |
12102101120112 has 80 divisors (see below), whose sum is σ = 32889988656000. Its totient is φ = 3828913322752.
The previous prime is 12102101120093. The next prime is 12102101120147. The reversal of 12102101120112 is 21102110120121.
It is a happy number.
It is a super-2 number, since 2×121021011201122 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 12102101120091 and 12102101120100.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 73596162 + ... + 73760417.
It is an arithmetic number, because the mean of its divisors is an integer number (411124858200).
Almost surely, 212102101120112 is an apocalyptic number.
12102101120112 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
12102101120112 is an abundant number, since it is smaller than the sum of its proper divisors (20787887535888).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
12102101120112 is a wasteful number, since it uses less digits than its factorization.
12102101120112 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 147356678 (or 147356672 counting only the distinct ones).
The product of its (nonzero) digits is 16, while the sum is 15.
Adding to 12102101120112 its reverse (21102110120121), we get a palindrome (33204211240233).
Subtracting 12102101120112 from its reverse (21102110120121), we obtain a palindrome (9000009000009).
The spelling of 12102101120112 in words is "twelve trillion, one hundred two billion, one hundred one million, one hundred twenty thousand, one hundred twelve".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.079 sec. • engine limits •