Base | Representation |
---|---|
bin | 10110100010111100… |
… | …10111001011100000 |
3 | 1011020120102202221121 |
4 | 23101132113023200 |
5 | 144242202111000 |
6 | 5321033502024 |
7 | 605646060445 |
oct | 132136271340 |
9 | 34216382847 |
10 | 12104332000 |
11 | 5151641872 |
12 | 2419871914 |
13 | 11ab964037 |
14 | 82b8199cc |
15 | 4ac9cdb1a |
hex | 2d17972e0 |
12104332000 has 96 divisors (see below), whose sum is σ = 29821768704. Its totient is φ = 4828480000.
The previous prime is 12104331973. The next prime is 12104332003. The reversal of 12104332000 is 23340121.
It is a happy number.
12104332000 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a Harshad number since it is a multiple of its sum of digits (16).
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12104332003) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1528050 + ... + 1535950.
It is an arithmetic number, because the mean of its divisors is an integer number (310643424).
Almost surely, 212104332000 is an apocalyptic number.
12104332000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 12104332000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (14910884352).
12104332000 is an abundant number, since it is smaller than the sum of its proper divisors (17717436704).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
12104332000 is an equidigital number, since it uses as much as digits as its factorization.
12104332000 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 8309 (or 8291 counting only the distinct ones).
The product of its (nonzero) digits is 144, while the sum is 16.
Adding to 12104332000 its reverse (23340121), we get a palindrome (12127672121).
The spelling of 12104332000 in words is "twelve billion, one hundred four million, three hundred thirty-two thousand".
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