Base | Representation |
---|---|
bin | 1011001001001110001000… |
… | …1011100001110111011000 |
3 | 1121101101020112010011011110 |
4 | 2302103202023201313120 |
5 | 3101223212044320204 |
6 | 42020545225300320 |
7 | 2403152534310324 |
oct | 262234213416730 |
9 | 47341215104143 |
10 | 12253041401304 |
11 | 39a4538486950 |
12 | 145a87a9346a0 |
13 | 6ab5c28ca602 |
14 | 30509c2d2984 |
15 | 163ae2c5a889 |
hex | b24e22e1dd8 |
12253041401304 has 64 divisors (see below), whose sum is σ = 33422713943040. Its totient is φ = 3712450815360.
The previous prime is 12253041401291. The next prime is 12253041401317. The reversal of 12253041401304 is 40310414035221.
It is an interprime number because it is at equal distance from previous prime (12253041401291) and next prime (12253041401317).
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2039944 + ... + 5354199.
It is an arithmetic number, because the mean of its divisors is an integer number (522229905360).
Almost surely, 212253041401304 is an apocalyptic number.
It is an amenable number.
12253041401304 is an abundant number, since it is smaller than the sum of its proper divisors (21169672541736).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
12253041401304 is a wasteful number, since it uses less digits than its factorization.
12253041401304 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 7400440 (or 7400436 counting only the distinct ones).
The product of its (nonzero) digits is 11520, while the sum is 30.
Adding to 12253041401304 its reverse (40310414035221), we get a palindrome (52563455436525).
The spelling of 12253041401304 in words is "twelve trillion, two hundred fifty-three billion, forty-one million, four hundred one thousand, three hundred four".
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