Base | Representation |
---|---|
bin | 10010000100001001111… |
… | …000110000010001110100 |
3 | 11101200022002121021111220 |
4 | 102010021320300101310 |
5 | 130314402310440200 |
6 | 2350144015030340 |
7 | 155455221655521 |
oct | 22041170602164 |
9 | 4350262537456 |
10 | 1241411421300 |
11 | 439530424916 |
12 | 18071620b3b0 |
13 | 900abbb74ab |
14 | 4412833c148 |
15 | 2245a5714a0 |
hex | 12109e30474 |
1241411421300 has 72 divisors (see below), whose sum is σ = 3625385522976. Its totient is φ = 327949176960.
The previous prime is 1241411421293. The next prime is 1241411421361. The reversal of 1241411421300 is 31241141421.
It is a happy number.
It is a super-2 number, since 2×12414114213002 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 19304527 + ... + 19368726.
It is an arithmetic number, because the mean of its divisors is an integer number (50352576708).
Almost surely, 21241411421300 is an apocalyptic number.
1241411421300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
1241411421300 is an abundant number, since it is smaller than the sum of its proper divisors (2383974101676).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1241411421300 is a wasteful number, since it uses less digits than its factorization.
1241411421300 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 38673377 (or 38673370 counting only the distinct ones).
The product of its (nonzero) digits is 768, while the sum is 24.
Adding to 1241411421300 its reverse (31241141421), we get a palindrome (1272652562721).
The spelling of 1241411421300 in words is "one trillion, two hundred forty-one billion, four hundred eleven million, four hundred twenty-one thousand, three hundred".
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