Base | Representation |
---|---|
bin | 1011011001100001100001… |
… | …1110101001001101101000 |
3 | 1122101011012001022011201210 |
4 | 2312120120132221031220 |
5 | 3120320320031143130 |
6 | 42353345510313120 |
7 | 2432326345635354 |
oct | 266303036511550 |
9 | 48334161264653 |
10 | 12533125256040 |
11 | 3aa22a5518464 |
12 | 14a50063587a0 |
13 | 6cbb3a53137c |
14 | 31486c33a464 |
15 | 16b036c145b0 |
hex | b66187a9368 |
12533125256040 has 64 divisors (see below), whose sum is σ = 39811103760960. Its totient is φ = 3145568691200.
The previous prime is 12533125256009. The next prime is 12533125256053. The reversal of 12533125256040 is 4065252133521.
It is a self number, because there is not a number n which added to its sum of digits gives 12533125256040.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 3071842386 + ... + 3071846465.
It is an arithmetic number, because the mean of its divisors is an integer number (622048496265).
Almost surely, 212533125256040 is an apocalyptic number.
12533125256040 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
12533125256040 is an abundant number, since it is smaller than the sum of its proper divisors (27277978504920).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
12533125256040 is a wasteful number, since it uses less digits than its factorization.
12533125256040 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6143688882 (or 6143688878 counting only the distinct ones).
The product of its (nonzero) digits is 216000, while the sum is 39.
Adding to 12533125256040 its reverse (4065252133521), we get a palindrome (16598377389561).
The spelling of 12533125256040 in words is "twelve trillion, five hundred thirty-three billion, one hundred twenty-five million, two hundred fifty-six thousand, forty".
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