Base | Representation |
---|---|
bin | 1011011010101001001010… |
… | …0010110100100001110100 |
3 | 1122102222211001202211101222 |
4 | 2312222102202310201310 |
5 | 3121124204334244000 |
6 | 42410245452405512 |
7 | 2433610003256120 |
oct | 266522242644164 |
9 | 48388731684358 |
10 | 12552353040500 |
11 | 3aaa472063519 |
12 | 14a8891776898 |
13 | 7008b2c33820 |
14 | 315773c4a580 |
15 | 16b7aec95a85 |
hex | b6a928b4874 |
12552353040500 has 96 divisors (see below), whose sum is σ = 33740725095168. Its totient is φ = 3972612816000.
The previous prime is 12552353040499. The next prime is 12552353040517. The reversal of 12552353040500 is 504035325521.
It is a super-3 number, since 3×125523530405003 (a number of 40 digits) contains 333 as substring.
It is a Harshad number since it is a multiple of its sum of digits (35).
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 137892446 + ... + 137983445.
It is an arithmetic number, because the mean of its divisors is an integer number (351465886408).
Almost surely, 212552353040500 is an apocalyptic number.
12552353040500 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
12552353040500 is an abundant number, since it is smaller than the sum of its proper divisors (21188372054668).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
12552353040500 is a wasteful number, since it uses less digits than its factorization.
12552353040500 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 275875930 (or 275875918 counting only the distinct ones).
The product of its (nonzero) digits is 90000, while the sum is 35.
The spelling of 12552353040500 in words is "twelve trillion, five hundred fifty-two billion, three hundred fifty-three million, forty thousand, five hundred".
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