Base | Representation |
---|---|
bin | 110000011111… |
… | …100001110010 |
3 | 212220211122200 |
4 | 300133201302 |
5 | 11223241200 |
6 | 1132244030 |
7 | 213023241 |
oct | 60374162 |
9 | 25824580 |
10 | 12712050 |
11 | 71a282a |
12 | 4310616 |
13 | 2831130 |
14 | 198c958 |
15 | 11b1800 |
hex | c1f872 |
12712050 has 144 divisors (see below), whose sum is σ = 38388168. Its totient is φ = 2995200.
The previous prime is 12712033. The next prime is 12712057. The reversal of 12712050 is 5021721.
12712050 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It can be written as a sum of positive squares in 12 ways, for example, as 159201 + 12552849 = 399^2 + 3543^2 .
It is a Harshad number since it is a multiple of its sum of digits (18).
It is a Curzon number.
It is not an unprimeable number, because it can be changed into a prime (12712057) by changing a digit.
It is a polite number, since it can be written in 71 ways as a sum of consecutive naturals, for example, 239824 + ... + 239876.
Almost surely, 212712050 is an apocalyptic number.
12712050 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is a practical number, because each smaller number is the sum of distinct divisors of 12712050, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (19194084).
12712050 is an abundant number, since it is smaller than the sum of its proper divisors (25676118).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
12712050 is a wasteful number, since it uses less digits than its factorization.
12712050 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 125 (or 117 counting only the distinct ones).
The product of its (nonzero) digits is 140, while the sum is 18.
The square root of 12712050 is about 3565.3961911687. The cubic root of 12712050 is about 233.3844219199.
Adding to 12712050 its reverse (5021721), we get a palindrome (17733771).
It can be divided in two parts, 1271 and 2050, that added together give a triangular number (3321 = T81).
The spelling of 12712050 in words is "twelve million, seven hundred twelve thousand, fifty".
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