1300321103232 has 64 divisors (see below), whose sum is σ = 3454096665600. Its totient is φ = 433425467904.

The previous prime is 1300321103231. The next prime is 1300321103281. The reversal of 1300321103232 is 2323011230031.

It is a tau number, because it is divible by the number of its divisors (64).

It is a junction number, because it is equal to n+sod(n) for n = 1300321103199 and 1300321103208.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1300321103231) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 21876369 + ... + 21935727.

It is an arithmetic number, because the mean of its divisors is an integer number (53970260400).

Almost surely, 2^{1300321103232} is an apocalyptic number.

1300321103232 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

1300321103232 is an abundant number, since it is smaller than the sum of its proper divisors (2153775562368).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1300321103232 is an equidigital number, since it uses as much as digits as its factorization.

1300321103232 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 116423 (or 116411 counting only the distinct ones).

The product of its (nonzero) digits is 648, while the sum is 21.

Adding to 1300321103232 its reverse (2323011230031), we get a palindrome (3623332333263).

The spelling of 1300321103232 in words is "one trillion, three hundred billion, three hundred twenty-one million, one hundred three thousand, two hundred thirty-two".