13004401140 has 144 divisors (see below), whose sum is σ = 39835832400. Its totient is φ = 3433789440.

The previous prime is 13004401139. The next prime is 13004401159. The reversal of 13004401140 is 4110440031.

It can be written as a sum of positive squares in 8 ways, for example, as 191844 + 13004209296 = 438^2 + 114036^2 .

It is a super-2 number, since 2×13004401140² (a number of 21 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 12256210 + ... + 12257270.

It is an arithmetic number, because the mean of its divisors is an integer number (276637725).

Almost surely, 2^13004401140 is an apocalyptic number.

13004401140 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 13004401140, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (19917916200).

13004401140 is an abundant number, since it is smaller than the sum of its proper divisors (26831431260).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13004401140 is a wasteful number, since it uses less digits than its factorization.

13004401140 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1682 (or 1677 counting only the distinct ones).

The product of its (nonzero) digits is 192, while the sum is 18.

Adding to 13004401140 its reverse (4110440031), we get a palindrome (17114841171).

The spelling of 13004401140 in words is "thirteen billion, four million, four hundred one thousand, one hundred forty".