Base | Representation |
---|---|
bin | 11101100100011111110000… |
… | …001111011000001000000000 |
3 | 122001110210020212021201022002 |
4 | 131210133300033120020000 |
5 | 114021230123400142100 |
6 | 1140332432510203132 |
7 | 36251620400543342 |
oct | 3544376017301000 |
9 | 561423225251262 |
10 | 130051345318400 |
11 | 38490514000970 |
12 | 127049a44b34a8 |
13 | 5774a34c693ac |
14 | 2418739449292 |
15 | 1007e020d12d5 |
hex | 7647f03d8200 |
130051345318400 has 120 divisors (see below), whose sum is σ = 351504402148944. Its totient is φ = 47291398246400.
The previous prime is 130051345318381. The next prime is 130051345318487. The reversal of 130051345318400 is 4813543150031.
It is a happy number.
It is an unprimeable number.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 461689262 + ... + 461970861.
Almost surely, 2130051345318400 is an apocalyptic number.
130051345318400 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
130051345318400 is an abundant number, since it is smaller than the sum of its proper divisors (221453056830544).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
130051345318400 is an equidigital number, since it uses as much as digits as its factorization.
130051345318400 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 923660162 (or 923660141 counting only the distinct ones).
The product of its (nonzero) digits is 86400, while the sum is 38.
Adding to 130051345318400 its reverse (4813543150031), we get a palindrome (134864888468431).
The spelling of 130051345318400 in words is "one hundred thirty trillion, fifty-one billion, three hundred forty-five million, three hundred eighteen thousand, four hundred".
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